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4.4 - Physical and Chemical Changes

Overview

Topic 4.1 sorted changes by what you can see. This topic explains the difference at the particle level. Chemical changes break and form chemical bonds. Physical changes usually change only intermolecular interactions, the weaker attractions between particles. You'll also see a case where the line is blurry, dissolving a salt, and how to argue it with evidence.

Bonds versus intermolecular interactions

Two kinds of attraction hold matter together:
  • Chemical bonds hold atoms together within a substance: covalent bonds inside molecules, ionic bonds between the ions in an ionic solid, and metallic bonds in metals (Unit 2). They are strong.
  • Intermolecular interactions, or intermolecular forces, are attractions between separate particles: London dispersion forces, dipole-dipole forces, hydrogen bonds, and ion-dipole interactions (Unit 3). They are much weaker.
That gives the general rule:
Chemical process
Physical process
What happens
Chemical bonds break and/or form
Only intermolecular interactions change
Particles afterward
New substances with new formulas
The same particles, rearranged or spread out
Energy involved
Large: breaking one mole of a typical covalent bond takes a few hundred kJ
Smaller: overcoming intermolecular forces usually takes a few to tens of kJ per mole
Examples
Burning, rusting, decomposing, forming a precipitate
Melting, boiling, sublimation, dissolving sugar
Watch the name: a hydrogen bond is an intermolecular interaction, not a chemical bond. Boiling water breaks hydrogen bonds between water molecules, while the O-H covalent bonds inside each molecule stay intact.

One substance, two kinds of change

Water shows the difference clearly. Boiling overcomes the hydrogen bonds between molecules, and every molecule leaves intact:
H2O(l)→H2O(g)\mathrm{H_2O(l) \rightarrow H_2O(g)}
Decomposing water breaks the O-H covalent bonds and forms new H-H and O=O bonds, so the products are new substances:
2H2O(l)→2H2(g)+O2(g)\mathrm{2H_2O(l) \rightarrow 2H_2(g) + O_2(g)}
The energy needed shows how different these are. The bars below use standard values per mole of water: melting at 0 °C, boiling at 100 °C, and decomposing at 25 °C. Decomposing water takes about 7 times as much energy as boiling it, and more than 40 times as much as melting it. You'll work with energies like these in Unit 6.
4.4 - Physical and Chemical Changes

Connecting what you see to bonds and forces

The CED asks you to explain how macroscopic characteristics, the things you can observe and measure, connect to interactions at the particle level.
  • Physical properties such as melting point, boiling point, and vapor pressure depend on how strongly the particles attract each other. Stronger intermolecular forces mean a higher boiling point. Substances held together by bonds all the way through (ionic solids, metals, and network solids like quartz) have very high melting points.
  • Chemical properties such as flammability and reactivity depend on which bonds can break and which new bonds can form.
  • Energy and reversibility. Physical changes usually involve smaller energy changes and can often be reversed just by changing the temperature or pressure: cool the steam and you get liquid water back. Chemical changes make substances with new properties, and getting the original substances back takes another reaction.

When a physical process breaks bonds

The line isn't always sharp. Some processes that are usually called physical do break chemical bonds. The standard example is dissolving a salt:
NaCl(s)→Na+(aq)+Cl−(aq)\mathrm{NaCl(s) \rightarrow Na^{+}(aq) + Cl^{-}(aq)}
4.4 - Physical and Chemical Changes
When NaCl\mathrm{NaCl} dissolves, the ionic bonds holding Na+\mathrm{Na^{+}} and Cl−\mathrm{Cl^{-}} together in the crystal break, and new ion-dipole interactions form between the ions and water. Water is polar, so it lines up around each ion: the partially negative oxygen end points toward Na+\mathrm{Na^{+}}, and a partially positive hydrogen end points toward Cl−\mathrm{Cl^{-}}.
You could make a reasonable argument either way:
Argument that it's physical
Argument that it's chemical
No new substance forms: the ions in solution are the same ions that were in the crystal
Ionic bonds, which are chemical bonds, are broken
Evaporating the water gives back solid NaCl\mathrm{NaCl}
New interactions (ion-dipole) form between the ions and water
No ion changes its identity; only the attractions between particles change
The solution has a new property: it conducts electricity, and the solid doesn't
On the AP exam, either classification can earn credit. What earns the point is the reasoning: name what breaks (the ionic bonds between ions) and what forms (ion-dipole interactions with water).
Melting an ionic solid, or a covalent network solid like quartz, SiO2\mathrm{SiO_2}, is a similar case. It's a phase change, so it's usually called physical, but it breaks some of the bonds that hold the solid together.

Example 1: Supporting a claim with lab data (AP-style)

A student heats two white solids in open crucibles and records these data.
Sample A
Sample B
Mass before heating
2.50 g
2.50 g
While heating
Melts at 69 °C; no gas given off
Doesn't melt; gives off a gas that turns limewater cloudy
Mass after cooling
2.50 g
1.59 g
Heated a second time
Melts at 69 °C again
No further change in mass
(a) Which sample went through a chemical change? Support your claim with evidence from the data.
Answer: Sample B. Its mass dropped from 2.50 g to 1.59 g, so something left as a gas, and that gas turned limewater cloudy, which is the test for carbon dioxide. A new substance formed. Sample A's mass didn't change, and it melted at the same temperature both times, so it was the same substance the whole time.
(b) Explain each result at the particle level.
Answer: Sample A is stearic acid, C18H36O2\mathrm{C_{18}H_{36}O_2}, a waxy solid. Melting only overcomes the intermolecular forces between its molecules (mostly London dispersion forces along their long carbon chains); the covalent bonds inside each molecule stay intact. Sample B is sodium hydrogen carbonate (baking soda), which decomposes:
2NaHCO3(s)→Na2CO3(s)+H2O(g)+CO2(g)\mathrm{2NaHCO_3(s) \rightarrow Na_2CO_3(s) + H_2O(g) + CO_2(g)}
Bonds inside the hydrogen carbonate ions break, and new substances (carbonate ions, water, and carbon dioxide) form. The water and carbon dioxide leave as gases, which is why the mass drops.
(c) Is Sample B's final mass consistent with this equation? Use 84.01 g/mol for NaHCO3\mathrm{NaHCO_3} and 105.99 g/mol for Na2CO3\mathrm{Na_2CO_3}.
2.50 g NaHCO3×1 mol NaHCO384.01 g NaHCO3×1 mol Na2CO32 mol NaHCO3×105.99 g Na2CO31 mol Na2CO3=1.58 g Na2CO32.50\ \mathrm{g\ NaHCO_3} \times \frac{1\ \mathrm{mol\ NaHCO_3}}{84.01\ \mathrm{g\ NaHCO_3}} \times \frac{1\ \mathrm{mol\ Na_2CO_3}}{2\ \mathrm{mol\ NaHCO_3}} \times \frac{105.99\ \mathrm{g\ Na_2CO_3}}{1\ \mathrm{mol\ Na_2CO_3}} = 1.58\ \mathrm{g\ Na_2CO_3}
Answer: Yes. The predicted 1.58 g is very close to the measured 1.59 g, which supports the claim that the baking soda decomposed. Topic 4.5 covers calculations like this one.

Example 2: Classifying at the particle level

For each process, say what is broken and what is formed, then classify it.
Process
Broken
Formed
Classification
I2(s)→I2(g)\mathrm{I_2(s) \rightarrow I_2(g)}
London dispersion forces between I2\mathrm{I_2} molecules
Nothing new; the molecules spread out
Physical
C2H5OH(l)→C2H5OH(aq)\mathrm{C_2H_5OH(l) \rightarrow C_2H_5OH(aq)} (ethanol mixing with water)
Hydrogen bonds between ethanol molecules and between water molecules
Hydrogen bonds between ethanol and water
Physical
HCl(g)+H2O(l)→H3O+(aq)+Cl−(aq)\mathrm{HCl(g) + H_2O(l) \rightarrow H_3O^{+}(aq) + Cl^{-}(aq)}
The H-Cl covalent bond
A new O-H covalent bond in H3O+\mathrm{H_3O^{+}}
Chemical
KBr(s)→K+(aq)+Br−(aq)\mathrm{KBr(s) \rightarrow K^{+}(aq) + Br^{-}(aq)}
Ionic bonds in the crystal
Ion-dipole interactions with water
Either, with reasoning
CH4(g)+2O2(g)→CO2(g)+2H2O(g)\mathrm{CH_4(g) + 2O_2(g) \rightarrow CO_2(g) + 2H_2O(g)}
C-H and O=O bonds
C=O and O-H bonds
Chemical
Dissolving HCl\mathrm{HCl} gas looks just like dissolving, but a covalent bond breaks and a new one forms, so it's a chemical change. It's an acid-base reaction, which Topic 4.8 covers.

Lab connection

Labs that separate or identify the parts of a mixture, like the AP lab that identifies the components of a pain reliever tablet, rely on physical properties such as solubility, melting point, and polarity. Those steps change only intermolecular interactions, so each component keeps its identity and can be recovered.

Common mistakes

  • Saying that boiling water breaks the bonds in water molecules. It breaks hydrogen bonds between molecules; the O-H bonds inside them stay.
  • Treating a hydrogen bond as a covalent bond because of its name.
  • Claiming physical changes never break chemical bonds. Dissolving or melting an ionic solid does.
  • Classifying the dissolving of a salt without saying what breaks and what forms. The explanation is what scores.
  • Calling every dissolving process physical. Dissolving HCl\mathrm{HCl} gas forms new covalent bonds, so it's a chemical change.

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