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1.15 - Connecting Limits at Infinity and Horizontal Asymptotes

Introduction to Horizontal Asymptotes

A horizontal asymptote describes the end behavior of a function, meaning what happens to the yy-values as xx heads toward positive or negative infinity.

Key Difference from Vertical Asymptotes

Horizontal asymptotes:
  • Describe behavior as x→±∞x \to \pm\infty
  • The graph CAN cross the asymptote
  • Represent the value the function approaches in the long run
Vertical asymptotes:
  • Occur at specific xx-values where the function is undefined
  • The graph CANNOT cross the asymptote
  • The function approaches ±∞\pm\infty near the asymptote

Visual Understanding

1.15 - Connecting Limits at Infinity and Horizontal Asymptotes
As x→∞x \to \infty, the function approaches y=2y = 2. Notice the graph crosses the asymptote several times, which is totally allowed for horizontal asymptotes.

Limit Notation for End Behavior

Horizontal asymptotes get written with limits.
Right-end behavior (as xx goes to positive infinity):
lim⁡x→∞f(x)=L\lim_{x \to \infty} f(x) = L
Left-end behavior (as xx goes to negative infinity):
lim⁡x→−∞f(x)=L\lim_{x \to -\infty} f(x) = L
If either limit equals a finite number LL, then y=Ly = L is a horizontal asymptote.

Growth Rates of Functions

To find horizontal asymptotes of rational functions, you need to know which types of functions grow fastest.

Ranking by Growth Rate (Fastest to Slowest)

Think about very large values of xx, like x=1000x = 1000.
1. Exponential functions (fastest)
  • Examples: 4x4^x, exe^x, 2x2^x
  • Growth: extremely rapid
2. Polynomial functions (moderate)
  • Examples: x60x^{60}, x3x^3, x2x^2
  • Growth: depends on the degree (higher degree means faster)
3. Logarithmic functions (slowest)
  • Examples: ln⁡(x)\ln(x), log⁡(x)\log(x)
  • Growth: very slow, but it never levels off. ln⁡x\ln x keeps growing without bound, so it has no horizontal asymptote

Comparison Table

xx
ln⁡(x)\ln(x)
x2x^2
x10x^{10}
2x2^x
10
2.3
100
101010^{10}
1024
100
4.6
10,000
102010^{20}
1.27×10301.27 \times 10^{30}
Key insight: for large xx, exponential functions dominate everything else.

Comparing Growth with Limits

To compare how fast two functions grow, take the limit of their ratio as x→∞x \to \infty:
  • If lim⁡x→∞f(x)g(x)=∞\lim_{x \to \infty} \frac{f(x)}{g(x)} = \infty, then ff grows faster than gg
  • If lim⁡x→∞f(x)g(x)=0\lim_{x \to \infty} \frac{f(x)}{g(x)} = 0, then ff grows slower than gg
  • If lim⁡x→∞f(x)g(x)\lim_{x \to \infty} \frac{f(x)}{g(x)} is a positive number, they grow at the same rate
For example:
  • lim⁡x→∞x3ex=0\lim_{x \to \infty} \frac{x^3}{e^x} = 0, so exe^x grows faster than x3x^3
  • lim⁡x→∞ln⁡xx=0\lim_{x \to \infty} \frac{\ln x}{\sqrt{x}} = 0, so x\sqrt{x} grows faster than ln⁡x\ln x
  • lim⁡x→∞4x2+xx2=4\lim_{x \to \infty} \frac{4x^2 + x}{x^2} = 4, so 4x2+x4x^2 + x and x2x^2 grow at the same rate
The rules below for rational functions are this same comparison: the limit at infinity depends on whether the numerator or the denominator grows faster. (L’Hospital’s Rule in Unit 4 gives a way to prove limits like x3ex→0\frac{x^3}{e^x} \to 0.)

Rules for Horizontal Asymptotes of Rational Functions

For rational functions f(x)g(x)\frac{f(x)}{g(x)}:

Rule 1: Denominator Grows Faster

If the denominator grows faster than the numerator:
lim⁡x→∞f(x)g(x)=0\lim_{x \to \infty} \frac{f(x)}{g(x)} = 0
Horizontal asymptote: y=0y = 0
Intuition: a small number divided by a huge number approaches zero.

Rule 2: Same Growth Rate

If the numerator and denominator grow at the same rate:
lim⁡x→∞f(x)g(x)=leading coefficient of numeratorleading coefficient of denominator\lim_{x \to \infty} \frac{f(x)}{g(x)} = \frac{\text{leading coefficient of numerator}}{\text{leading coefficient of denominator}}
Intuition: the ratio of the leading terms sets the asymptote.

Rule 3: Numerator Grows Faster

If the numerator grows faster than the denominator:
lim⁡x→∞f(x)g(x)=±∞\lim_{x \to \infty} \frac{f(x)}{g(x)} = \pm\infty
No horizontal asymptote (the function grows without bound).

Finding Horizontal Asymptotes: Examples

Example 1: Denominator Grows Faster

Find lim⁡x→∞5xx2+3\lim_{x \to \infty} \dfrac{5x}{x^2 + 3}.
Dominant terms:
  • Numerator: 5x5x (degree 1)
  • Denominator: x2x^2 (degree 2)
The denominator (x2x^2) grows faster than the numerator (xx), so by Rule 1:
lim⁡x→∞5xx2+3=0\lim_{x \to \infty} \frac{5x}{x^2 + 3} = 0
Answer: horizontal asymptote at y=0y = 0

Example 2: Same Growth Rate

Find lim⁡x→∞3x+7x−2\lim_{x \to \infty} \dfrac{3x + 7}{x - 2}.
Dominant terms:
  • Numerator: 3x3x (degree 1)
  • Denominator: xx (degree 1)
Both are degree 1, so they have the same growth rate. By Rule 2, look only at the leading coefficients:
lim⁡x→∞3x+7x−2=31=3\lim_{x \to \infty} \frac{3x + 7}{x - 2} = \frac{3}{1} = 3
Answer: horizontal asymptote at y=3y = 3
Note: the constants +7+7 and −2-2 don’t matter for end behavior.

Example 3: Higher Degree Polynomials

Find lim⁡x→∞2x3−5x2+7x−16x3+4x−8\lim_{x \to \infty} \dfrac{2x^3 - 5x^2 + 7x - 1}{6x^3 + 4x - 8}.
Focus only on the highest degree terms:
lim⁡x→∞2x3−5x2+7x−16x3+4x−8=lim⁡x→∞2x36x3=26=13\lim_{x \to \infty} \frac{2x^3 - 5x^2 + 7x - 1}{6x^3 + 4x - 8} = \lim_{x \to \infty} \frac{2x^3}{6x^3} = \frac{2}{6} = \frac{1}{3}
Answer: horizontal asymptote at y=13y = \frac{1}{3}

Example 4: Numerator Grows Faster

Find lim⁡x→∞x32x+5\lim_{x \to \infty} \dfrac{x^3}{2x + 5}.
Compare degrees:
  • Numerator: degree 3
  • Denominator: degree 1
The numerator grows faster, so as xx gets large, the numerator becomes much bigger than the denominator.
lim⁡x→∞x32x+5=∞\lim_{x \to \infty} \frac{x^3}{2x + 5} = \infty
Answer: no horizontal asymptote (the function grows without bound)

Square Roots and Radicals

With square roots, you have to be careful about the sign of the result.

Example 5: Square Root in the Numerator

Find lim⁡x→∞4x2+13x\lim_{x \to \infty} \dfrac{\sqrt{4x^2 + 1}}{3x}.
Simplify the square root for large positive xx:
4x2+1≈4x2=2∣x∣=2x(for x>0)\sqrt{4x^2 + 1} \approx \sqrt{4x^2} = 2|x| = 2x \quad \text{(for } x > 0\text{)}
Evaluate:
lim⁡x→∞2x3x=23\lim_{x \to \infty} \frac{2x}{3x} = \frac{2}{3}
Answer: y=23y = \frac{2}{3}

Example 6: Negative Infinity with a Square Root

Find lim⁡x→−∞4x2+13x\lim_{x \to -\infty} \dfrac{\sqrt{4x^2 + 1}}{3x}.
Critical distinction: when x<0x < 0
4x2+1≈4x2=2∣x∣=2(−x)=−2x\sqrt{4x^2 + 1} \approx \sqrt{4x^2} = 2|x| = 2(-x) = -2x
The absolute value makes this positive, but since xx is negative, we write it as −2x-2x (which is positive).
Evaluate:
lim⁡x→−∞−2x3x=−23=−23\lim_{x \to -\infty} \frac{-2x}{3x} = \frac{-2}{3} = -\frac{2}{3}
Answer: y=−23y = -\frac{2}{3}
Important: this function has TWO different horizontal asymptotes.
  • As x→∞x \to \infty: y=23y = \frac{2}{3}
  • As x→−∞x \to -\infty: y=−23y = -\frac{2}{3}

Example 7: Even Power Under a Radical

Find the horizontal asymptotes of
f(x)=4x43x2f(x) = \frac{\sqrt{4x^4}}{3x^2}
Simplify the radical:
4x4=4⋅x4=2x2\sqrt{4x^4} = \sqrt{4} \cdot \sqrt{x^4} = 2x^2
Note that x4=x2\sqrt{x^4} = x^2, which is always positive because it’s an even power.
As x→∞x \to \infty:
lim⁡x→∞2x23x2=23\lim_{x \to \infty} \frac{2x^2}{3x^2} = \frac{2}{3}
As x→−∞x \to -\infty: since x4x^4 is always positive (even power),
lim⁡x→−∞2x23x2=23\lim_{x \to -\infty} \frac{2x^2}{3x^2} = \frac{2}{3}
Answer: only one horizontal asymptote, y=23y = \frac{2}{3}, in both directions.

Exponential Functions and Limits at Infinity

Example 8: Exponential in the Numerator

Find lim⁡x→∞5exx100\lim_{x \to \infty} \dfrac{5e^x}{x^{100}}.
Exponential functions grow much faster than any polynomial, so
lim⁡x→∞5exx100=∞\lim_{x \to \infty} \frac{5e^x}{x^{100}} = \infty
Answer: no horizontal asymptote

Example 9: Exponential with a Negative Exponent

Find lim⁡x→∞3e−x\lim_{x \to \infty} 3e^{-x}.
Rewrite with a positive exponent:
3e−x=3ex3e^{-x} = \frac{3}{e^x}
As x→∞x \to \infty, ex→∞e^x \to \infty, so
lim⁡x→∞3ex=0\lim_{x \to \infty} \frac{3}{e^x} = 0
Answer: y=0y = 0

Example 10: Exponential with a Fraction

Find lim⁡x→∞−4e1x\lim_{x \to \infty} -4e^{\frac{1}{x}}.
Step 1: Evaluate the exponent. As x→∞x \to \infty, 1x→0\frac{1}{x} \to 0.
Step 2: Evaluate ee to that power: e0=1e^0 = 1.
Step 3: Multiply by the coefficient: −4⋅1=−4-4 \cdot 1 = -4.
Answer: y=−4y = -4

Trigonometric Functions and Limits at Infinity

Special Trig Limit (Review)

lim⁡x→0sin⁡xx=1\lim_{x \to 0} \frac{\sin x}{x} = 1
This ONLY works when x→0x \to 0.

Example 11: Sine Over a Large Number

Find lim⁡x→∞sin⁡xx\lim_{x \to \infty} \dfrac{\sin x}{x}.
Common mistake: thinking this equals 1. It doesn’t. That result only applies when x→0x \to 0.
Correct reasoning:
  • Numerator: sin⁡x\sin x oscillates between −1-1 and 11 (bounded)
  • Denominator: x→∞x \to \infty (unbounded)
lim⁡x→∞sin⁡xx=boundedvery large=0\lim_{x \to \infty} \frac{\sin x}{x} = \frac{\text{bounded}}{\text{very large}} = 0
Answer: y=0y = 0

Example 12: Cosine of a Small Value

Find lim⁡x→∞−3cos⁡(1x)\lim_{x \to \infty} -3\cos\left(\dfrac{1}{x}\right).
Step 1: As x→∞x \to \infty, 1x→0\frac{1}{x} \to 0.
Step 2: Evaluate cosine: cos⁡(0)=1\cos(0) = 1.
Step 3: Multiply: −3⋅1=−3-3 \cdot 1 = -3.
Answer: y=−3y = -3

Example 13: Unbounded Oscillation

Find lim⁡x→∞sin⁡x\lim_{x \to \infty} \sin x.
The sine function oscillates between −1-1 and 11 forever and never settles on a single value.
1.15 - Connecting Limits at Infinity and Horizontal Asymptotes
Answer: does not exist (DNE), because the function oscillates without approaching a specific value.

Example 14: Growing Oscillation

Find lim⁡x→∞(5xcos⁡x)\lim_{x \to \infty} (5x \cos x).
While cos⁡x\cos x oscillates between −1-1 and 11, the factor 5x5x grows without bound. The product oscillates with increasing amplitude:
  • Sometimes near +5x+5x (when cos⁡x≈1\cos x \approx 1)
  • Sometimes near −5x-5x (when cos⁡x≈−1\cos x \approx -1)
The oscillation just gets bigger and bigger.
Answer: does not exist (DNE), because it oscillates with unbounded amplitude.

Practice Problems

Problem 1

Find lim⁡x→∞7x2−32x2+5x\lim_{x \to \infty} \dfrac{7x^2 - 3}{2x^2 + 5x}.
Answer: same degree (both x2x^2), so the limit is 72\frac{7}{2}.

Problem 2

Find lim⁡x→∞x+1x3\lim_{x \to \infty} \dfrac{x + 1}{x^3}.
Answer: the denominator grows faster, so the limit is 00.

Problem 3

Find lim⁡x→∞9x2+xx\lim_{x \to \infty} \dfrac{\sqrt{9x^2 + x}}{x}.
Answer: 9x2=3x\sqrt{9x^2} = 3x for x>0x > 0, so the result is 3xx=3\frac{3x}{x} = 3.

Problem 4

Find lim⁡x→−∞9x2+xx\lim_{x \to -\infty} \dfrac{\sqrt{9x^2 + x}}{x}.
Answer: 9x2=3∣x∣=−3x\sqrt{9x^2} = 3|x| = -3x for x<0x < 0, so the result is −3xx=−3\frac{-3x}{x} = -3.

Problem 5

Find lim⁡x→∞cos⁡xx2\lim_{x \to \infty} \dfrac{\cos x}{x^2}.
Answer: bounded numerator over unbounded denominator, so the limit is 00.

Key Takeaways

  • Horizontal asymptotes describe end behavior as x→±∞x \to \pm\infty
  • Graphs can cross horizontal asymptotes, unlike vertical ones
  • Growth rate hierarchy: exponential beats polynomial beats logarithmic
  • Compare growth with a limit: if lim⁡x→∞f(x)g(x)=∞\lim_{x \to \infty} \frac{f(x)}{g(x)} = \infty, ff grows faster; if it’s 00, gg grows faster
  • For rational functions, compare the degrees of the numerator and denominator
  • Only the highest degree terms matter for end behavior
  • With square roots, x2=∣x∣\sqrt{x^2} = |x|, which equals xx if x>0x > 0 and −x-x if x<0x < 0
  • Even powers under radicals are always positive: x4=x2\sqrt{x^4} = x^2
  • lim⁡x→0sin⁡xx=1\lim_{x \to 0} \frac{\sin x}{x} = 1 only works for x→0x \to 0, not x→∞x \to \infty
  • sin⁡xx→0\frac{\sin x}{x} \to 0 as x→∞x \to \infty (bounded over unbounded)
  • Unbounded trig oscillations mean the limit does not exist
  • A function can have different horizontal asymptotes on the left and right
  • Exponentials with negative exponents approach zero: e−x→0e^{-x} \to 0 as x→∞x \to \infty

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