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1.1 - Change in Tandem

Overview

A function connects two quantities, so when one changes, the other changes with it. This topic is about describing that connection: what a function is, how to read one in any form (a graph, a table, an equation, or words), and how to describe the way its outputs change as its inputs increase. You'll use these words and ideas in every unit of AP Precalculus.

What a function is

A function is a rule that maps each input value to exactly one output value. You put in an input, and the rule gives back one output, never two.
  • Domain: the set of all input values the function accepts.
  • Range: the set of all output values the function produces.
  • Independent variable: the variable for the inputs (usually xx, or tt for time). You choose its value.
  • Dependent variable: the variable for the outputs (usually yy or f(x)f(x)). Its value depends on the input.
In function notation, f(3)=7f(3) = 7 means that when the input is 33, the output is 77. The input goes inside the parentheses, and the whole expression f(3)f(3) is an output value.
One input can't have two outputs, but two different inputs can share an output. For example, f(x)=x2f(x) = x^2 gives f(−3)=9f(-3) = 9 and f(3)=9f(3) = 9, and that's fine. On a graph, this means no vertical line crosses the graph more than once (the vertical line test).

When two functions are equal

Two functions ff and gg are equal when they have the same domain and give the same output for every input in that domain, so f(a)=g(a)f(a) = g(a) for every aa. Both parts matter.

Example 1: Are these functions equal?

Are f(x)=x+2f(x) = x + 2 and g(x)=x2−4x−2g(x) = \frac{x^2 - 4}{x - 2} equal?
Step 1: Simplify gg where you can.
g(x)=(x−2)(x+2)x−2=x+2for x≠2g(x) = \frac{(x - 2)(x + 2)}{x - 2} = x + 2 \quad \text{for } x \neq 2
Step 2: Compare the domains. The domain of ff is all real numbers. But g(2)=00g(2) = \frac{0}{0} is undefined, so x=2x = 2 is not in the domain of gg.
Answer: The outputs match for every x≠2x \neq 2, but the domains are different, so ff and gg are not equal. Their graphs look the same, except the graph of gg has a hole at (2,4)(2, 4).

Four ways to represent a function

The input and output values of a function vary in tandem: they change together according to the function rule. AP Precalculus expects you to work with that rule in four forms. Here is one function written all four ways:
Representation
What it looks like
Example
Verbal
Words
The output is 33 more than twice the input.
Analytical
An equation
f(x)=2x+3f(x) = 2x + 3
Numerical
A table of values
f(0)=3f(0) = 3, f(1)=5f(1) = 5, f(2)=7f(2) = 7
Graphical
A graph
A line through (0,3)(0, 3) with slope 22
Each form shows something the others hide. A graph shows the overall shape at a glance, a table gives exact values at a few inputs, an equation lets you compute any output, and words connect the function to a real situation. On the exam, you'll often get one form and need to build or read another.

Image and preimage

The image of an input value is the single output the rule gives for it. The preimage of an output value is the set of all inputs that give that output. An image is always one value. A preimage can have one value, several values, or none at all.

Example 2: Finding images and preimages

Let f(x)=x2−4x+3f(x) = x^2 - 4x + 3. Find the image of 55, and the preimages of 33, −1-1, and −5-5.
Image of 5: plug in x=5x = 5.
f(5)=52−4(5)+3=25−20+3=8f(5) = 5^2 - 4(5) + 3 = 25 - 20 + 3 = 8
The image of 55 is 88.
Preimage of 3: solve f(x)=3f(x) = 3.
x2−4x+3=3  ⇒  x2−4x=0  ⇒  x(x−4)=0x^2 - 4x + 3 = 3 \;\Rightarrow\; x^2 - 4x = 0 \;\Rightarrow\; x(x - 4) = 0
So x=0x = 0 or x=4x = 4. The preimage of 33 is {0,4}\{0, 4\}, two inputs.
Preimage of -1: solve f(x)=−1f(x) = -1.
x2−4x+3=−1  ⇒  x2−4x+4=0  ⇒  (x−2)2=0x^2 - 4x + 3 = -1 \;\Rightarrow\; x^2 - 4x + 4 = 0 \;\Rightarrow\; (x - 2)^2 = 0
So the preimage of −1-1 is {2}\{2\}, just one input.
Preimage of -5: solve f(x)=−5f(x) = -5.
x2−4x+3=−5  ⇒  x2−4x+8=0x^2 - 4x + 3 = -5 \;\Rightarrow\; x^2 - 4x + 8 = 0
The discriminant is (−4)2−4(1)(8)=−16(-4)^2 - 4(1)(8) = -16, which is negative, so no real input works. The preimage of −5-5 is empty, which tells you −5-5 is not in the range of ff.

Increasing and decreasing

A function is increasing on an interval if its outputs always go up as its inputs go up. In symbols: for all aa and bb in the interval, if a<ba < b, then f(a)<f(b)f(a) < f(b).
A function is decreasing on an interval if its outputs always go down as its inputs go up: for all aa and bb in the interval, if a<ba < b, then f(a)>f(b)f(a) > f(b).
Read a graph from left to right, the direction the inputs increase. Uphill means increasing, and downhill means decreasing.
Exam note: the AP exam doesn't test whether an endpoint belongs in an interval where a function is increasing or decreasing. So for describing where a function increases or decreases, either (1,3)(1, 3) or [1,3][1, 3] is fine.
On free-response questions, name both the input and the output when you describe change, like this: "On the interval 1<x<31 < x < 3, as the value of xx increases, the value of f(x)f(x) decreases."

Concavity: How the rate of change behaves

Increasing and decreasing tell you which way the outputs move. Concavity tells you how the rate of change is behaving.
  • Concave up: the graph is concave up on intervals where the rate of change is increasing. It bends upward, like a cup.
  • Concave down: the graph is concave down on intervals where the rate of change is decreasing. It bends downward, like a cap.
Direction and concavity are separate ideas, so all four combinations are possible:
1.1 - Change in Tandem
The bottom row is where students slip. A graph that is decreasing and concave up is falling, but more and more slowly: its rate of change is negative and getting closer to 00, so the rate is increasing. A graph that is decreasing and concave down is falling faster and faster: its rate is negative and getting more negative.
A point where a graph switches concavity is called a point of inflection. You'll study these in Topic 1.4.

Zeros of a function

A zero of a function is an input value where the output is 00. On a graph, that's where the graph meets the xx-axis, since every point on the xx-axis has a yy-value of 00.
Watch the wording: if f(4)=0f(4) = 0, then x=4x = 4 is a zero (a number), and the point (4,0)(4, 0) is an xx-intercept.

Describing a graph

Every point (x,y)(x, y) on the graph of ff is an input-output pair, with y=f(x)y = f(x). Because a graph shows all of those pairs at once, you can see how the outputs change as the inputs increase, which is exactly what AP questions ask you to describe.

Example 3: Reading a graph (AP-style)

The graph of f(x)=x(x−3)2f(x) = x(x - 3)^2 is shown. (a) Find the zeros of ff. (b) On what intervals is ff increasing? Decreasing? (c) On what intervals is the graph of ff concave up? Concave down? (d) Describe how the values of f(x)f(x) change on the interval 1<x<31 < x < 3.
1.1 - Change in Tandem
(a) Zeros. The graph meets the xx-axis at x=0x = 0 and x=3x = 3. Check: f(0)=0(−3)2=0f(0) = 0(-3)^2 = 0 and f(3)=3(0)2=0f(3) = 3(0)^2 = 0.
(b) Increasing and decreasing. Reading left to right, the graph rises to the peak at (1,4)(1, 4), falls to (3,0)(3, 0), then rises again. So ff is increasing on (−∞,1)(-\infty, 1) and (3,∞)(3, \infty), and decreasing on (1,3)(1, 3).
(c) Concavity. The graph bends downward to the left of (2,2)(2, 2) and upward to the right of it. So the graph is concave down on (−∞,2)(-\infty, 2) and concave up on (2,∞)(2, \infty).
(d) In words: on the interval 1<x<31 < x < 3, as xx increases, f(x)f(x) decreases. It decreases faster and faster from x=1x = 1 to x=2x = 2, where the graph is concave down, then more and more slowly from x=2x = 2 to x=3x = 3, where the graph is concave up.

Building a graph from a description

A verbal description of how two quantities change together is enough to sketch a graph, even with no numbers. Ask two questions: is the output going up or down, and is it changing faster or slower as the input increases?

Example 4: Filling a flask

Water is poured at a constant rate into a flask that is wide at the bottom and narrow at the top. Sketch the height of the water as a function of time.
1.1 - Change in Tandem
Is the height increasing or decreasing? Water keeps coming in, so the height always increases.
Is it rising faster or slower? The same amount of water goes in every second. Near the bottom, the flask is wide, so the water spreads out and the height rises slowly. Higher up, the flask is narrow, so the same amount of water stacks up higher and the height rises faster.
Answer: the height increases at an increasing rate, so the graph is increasing and concave up.
If the flask were narrow at the bottom and wide at the top, the height would rise quickly at first and then more slowly, so its graph would be increasing and concave down.

Common mistakes

  • Reading a graph right to left. Increasing and decreasing describe what happens as the input increases, so always read left to right.
  • Mixing up a zero and an intercept. A zero is an input value like x=3x = 3. The xx-intercept is the point (3,0)(3, 0).
  • Ignoring the domain when comparing functions. Equal functions need the same domain, not just formulas that match after simplifying.
  • Thinking concave up means increasing. A concave up graph can be decreasing. Concavity is about whether the rate of change is increasing, not whether the outputs are.
  • Calling a preimage a single number. A preimage is a set of inputs. It can have several values, one, or none.

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